Students’ scores on a classroom test have a mean of 65 and a standard deviation of 8. What is the likely percentage of students who scored above 70? Please check the job 70-65/8=.625=.2357=1.-.2357=.7643
RESPONSE 76% ???? No, since the value is higher than the average, it would be lower than 50%.
Z = (mean of scores)/SD
Find a table at the back of your statistics text titled something like “areas under normal distribution” to find the proportion/probability related to the ZQ27 score) Science test scores are displayed. The class went very well. All of the students who took the test scored over 75. Unfortunately, 4 students were absent for the test and the computer listed their scores as 0 until the test was taken. Assuming that no score repeats more times than 0s, which measure of central tendency would likely give the best representation of this data?