**the heat of fusion of water is 79.9 cal/g, the heat of vaporization of water is 540 cal/g, and the specific heat of water is 1.00 cal/deg/g. how many grams of ice at 0 could be converted to steam at 100 c by 9,076 cal of heat?**

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**the heat of fusion of water is 79.9 cal/g, the heat of vaporization of water is 540 cal/g, and the specific heat of water is 1.00 cal/deg/g. how many grams of ice at 0 could be converted to steam at 100 c by 9,076 cal of heat?**

answer :q

2

=1 0×1 . 0 0×( 1 0 0−0 )=1 0 0 0 cal

Total heat required for entire process =q

1

+q

2

=8 0 0+1 0 0 0=1 8 0 0 cal